What is the derivative of y=ln(7x) ?

The derivative of y=ln(7x) is 1/x

What is the first derivative of y=ln(7x) ?

The first derivative of y=ln(7x) is 1/x

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derivative of

y = ln (7 x)

\frac{1}{x}

Solution steps

\frac{d}{d x} (ln (7 x))

Apply the chain rule:

\frac{1}{7 x} \frac{d}{d x} (7 x)

= \frac{1}{7 x} \frac{d}{d x} (7 x)

\frac{d}{d x} (7 x) = 7

= \frac{1}{7 x} \cdot 7

Simplify

\frac{1}{7 x} \cdot 7 : \frac{1}{x}

= \frac{1}{x}

\int x 49 - x d x

n = 0 \sum \infty 5

\int \frac{1}{( x - 2 ) ( x - 4 )} d x

\frac{\partial}{\partial y} (x^{3} + y^{3} - 6 x y)

\frac{\partial}{\partial x} (\frac{x ^{2} - x}{( L + 2 x ) ^{3}})

What is the derivative of y=ln(7x) ?
The derivative of y=ln(7x) is 1/x
What is the first derivative of y=ln(7x) ?
The first derivative of y=ln(7x) is 1/x