What is the integral from 0 to 4 of x^{1/2} ?

The integral from 0 to 4 of x^{1/2} is 16/3

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integral from 0 to 4 of x^{1/2}

\int_{0}^{4} x^{\frac{1}{2}} d x

\frac{16}{3}

Decimal Notation

5.33333 \dots

Solution steps

\int_{0}^{4} x^{\frac{1}{2}} d x

Apply the Power Rule

: [\frac{2}{3} x^{\frac{3}{2}}]_{0}^{4}

= [\frac{2}{3} x^{\frac{3}{2}}]_{0}^{4}

Compute the boundaries:

\frac{16}{3}

= \frac{16}{3}

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What is the integral from 0 to 4 of x^{1/2} ?
The integral from 0 to 4 of x^{1/2} is 16/3