What is the derivative of x/(sqrt(x)+7) ?

The derivative of x/(sqrt(x)+7) is (sqrt(x)+14)/(2(sqrt(x)+7)^2)

What is the first derivative of x/(sqrt(x)+7) ?

The first derivative of x/(sqrt(x)+7) is (sqrt(x)+14)/(2(sqrt(x)+7)^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

\frac{x}{x + 7}

\frac{x + 14}{2 ( x + 7 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x}{x + 7})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d x}{d x} ( x + 7 ) - \frac{d}{d x} ( x + 7 ) x}{( x + 7 ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (x + 7) = \frac{1}{2 x}

= \frac{1 \cdot ( x + 7 ) - \frac{1}{2 x} x}{( x + 7 ) ^{2}}

Simplify

\frac{1 \cdot ( x + 7 ) - \frac{1}{2 x} x}{( x + 7 ) ^{2}} : \frac{x + 14}{2 ( x + 7 ) ^{2}}

= \frac{x + 14}{2 ( x + 7 ) ^{2}}

\int sin^{2} (\frac{nπ x}{a}) d x

\int ln (x^{9}) d x

\frac{d}{d x} (\frac{8}{3})

x + 2, \frac{1}{x + 1}, 0, 2

\frac{d y}{d x} = \frac{( 2 x + 2 x y ^{2} )}{( y + 2 x ^{2} y )}

What is the derivative of x/(sqrt(x)+7) ?
The derivative of x/(sqrt(x)+7) is (sqrt(x)+14)/(2(sqrt(x)+7)^2)
What is the first derivative of x/(sqrt(x)+7) ?
The first derivative of x/(sqrt(x)+7) is (sqrt(x)+14)/(2(sqrt(x)+7)^2)