What is the derivative of y=e^x2^x ?

The derivative of y=e^x2^x is e^x*2^x+2^xln(2)e^x

What is the first derivative of y=e^x2^x ?

The first derivative of y=e^x2^x is e^x*2^x+2^xln(2)e^x

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derivative of

y = e^{x} 2^{x}

e^{x} \cdot 2^{x} + 2^{x} ln (2) e^{x}

Solution steps

\frac{d}{d x} (e^{x} \cdot 2^{x})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = e^{x}, g = 2^{x}

= \frac{d}{d x} (e^{x}) 2^{x} + \frac{d}{d x} (2^{x}) e^{x}

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (2^{x}) = 2^{x} ln (2)

= e^{x} \cdot 2^{x} + 2^{x} ln (2) e^{x}

y = 2 x^{2}, x = 2, y = 0

sec^{2} (t)

ln (x^{9})

\frac{d}{d x} (e^{x} + e^{x} \cdot x)

\int \frac{x ^{5}}{x + 1} d x

What is the derivative of y=e^x2^x ?
The derivative of y=e^x2^x is e^x*2^x+2^xln(2)e^x
What is the first derivative of y=e^x2^x ?
The first derivative of y=e^x2^x is e^x*2^x+2^xln(2)e^x