What is the derivative of ln(x^9) ?

The derivative of ln(x^9) is 9/x

What is the first derivative of ln(x^9) ?

The first derivative of ln(x^9) is 9/x

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derivative of

ln (x^{9})

\frac{9}{x}

Solution steps

\frac{d}{d x} (ln (x^{9}))

Apply the chain rule:

\frac{1}{x ^{9}} \frac{d}{d x} (x^{9})

= \frac{1}{x ^{9}} \frac{d}{d x} (x^{9})

\frac{d}{d x} (x^{9}) = 9 x^{8}

= \frac{1}{x ^{9}} \cdot 9 x^{8}

Simplify

\frac{1}{x ^{9}} \cdot 9 x^{8} : \frac{9}{x}

= \frac{9}{x}

\frac{d}{d x} (e^{x} + e^{x} \cdot x)

\int \frac{x ^{5}}{x + 1} d x

\frac{4 x}{x - 5}

y = tan (\frac{t}{1 + t ^{2}})

\int_{0}^{1} 4 π (x^{2} - x^{10}) d x

What is the derivative of ln(x^9) ?
The derivative of ln(x^9) is 9/x
What is the first derivative of ln(x^9) ?
The first derivative of ln(x^9) is 9/x