What is area y=sqrt(1-x^2),y=x^2-1 ?

The answer to area y=sqrt(1-x^2),y=x^2-1 is pi/2+4/3

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area y=sqrt(1-x^2),y=x^2-1

area

y = 1 - x^{2}, y = x^{2} - 1

\frac{π}{2} + \frac{4}{3}

Decimal Notation

2.90412 \dots

Solution steps

Apply the area formula:

\int_{- 1}^{1} 1 - x^{2} - (x^{2} - 1) d x

Solve

\int_{- 1}^{1} 1 - x^{2} - (x^{2} - 1) d x : \frac{π}{2} + \frac{4}{3}

The area is:

= \frac{π}{2} + \frac{4}{3}

x^{3} y y^{^{'}} + x^{2} y^{2} = y^{5}

\frac{\partial}{\partial y} (x^{2} e^{- \frac{x}{y}})

\int 13 e^{u} d u

f (x) = x^{2} - 3 x + 5, at x = 2

y^{^{'}} = \frac{y}{x} + 1 + (\frac{y}{x})^{2}

What is area y=sqrt(1-x^2),y=x^2-1 ?
The answer to area y=sqrt(1-x^2),y=x^2-1 is pi/2+4/3