What is the integral of 13e^u ?

The integral of 13e^u is 13e^u+C

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integral of 13e^u

\int 13 e^{u} d u

13 e^{u} + C

Solution steps

\int 13 e^{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 13 \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= 13 e^{u}

Add a constant to the solution

= 13 e^{u} + C

f (x) = x^{2} - 3 x + 5, at x = 2

y^{^{'}} = \frac{y}{x} + 1 + (\frac{y}{x})^{2}

\int \frac{x ^{2} - 12}{x ^{3} + 4 x} d x

\frac{\partial}{\partial x} ((2 x y + 3) e^{- x y})

\frac{d}{d x} (\frac{( x ^{2} - 2 e ^{x} )}{x + 3 e ^{x}})