What is the solution for (dy)/(dx)=(2x+1)/(2y) ?

The solution for (dy)/(dx)=(2x+1)/(2y) is y=sqrt(x^2+x+c_{1)},y=-sqrt(x^2+x+c_{1)}

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(dy)/(dx)=(2x+1)/(2y)

\frac{d y}{d x} = \frac{2 x + 1}{2 y}

y = x^{2} + x + c_{1}, y = - x^{2} + x + c_{1}

Solution steps

\frac{d y}{d x} = \frac{2 x + 1}{2 y}

Solve separable ODE:

y = x^{2} + x + c_{1}, y = - x^{2} + x + c_{1}

y = x^{2} + x + c_{1}, y = - x^{2} + x + c_{1}

f (x) = \frac{1}{x + 3}

(ln (x))^{^{'}}

\frac{d y}{d x} = (- 3 y)

\int 169 - x^{2} d x

\int \frac{8 x ^{3}}{( x ^{4} + 1 ) ^{3}} d x

What is the solution for (dy)/(dx)=(2x+1)/(2y) ?
The solution for (dy)/(dx)=(2x+1)/(2y) is y=sqrt(x^2+x+c_{1)},y=-sqrt(x^2+x+c_{1)}