What is the derivative of cos^9(t) ?

The derivative of cos^9(t) is -9cos^8(t)sin(t)

What is the first derivative of cos^9(t) ?

The first derivative of cos^9(t) is -9cos^8(t)sin(t)

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derivative of

cos^{9} (t)

- 9 cos^{8} (t) sin (t)

Solution steps

\frac{d}{d t} (cos^{9} (t))

Apply the chain rule:

9 (cos (t))^{8} \frac{d}{d t} (cos (t))

= 9 (cos (t))^{8} \frac{d}{d t} (cos (t))

\frac{d}{d t} (cos (t)) = - sin (t)

= 9 (cos (t))^{8} (- sin (t))

Simplify

= - 9 cos^{8} (t) sin (t)

\frac{\partial}{\partial x} (2 (y^{2} - x^{2}) ln (x + y))

3 x^{2} - x^{3}

\int \frac{1}{4 x ^{2} + 1} d x

\int \frac{1}{y + y} d y

y^{^{'}} = sin (x^{2})

What is the derivative of cos^9(t) ?
The derivative of cos^9(t) is -9cos^8(t)sin(t)
What is the first derivative of cos^9(t) ?
The first derivative of cos^9(t) is -9cos^8(t)sin(t)