What is the derivative of 3x^2-x^3 ?

The derivative of 3x^2-x^3 is 6x-3x^2

What is the first derivative of 3x^2-x^3 ?

The first derivative of 3x^2-x^3 is 6x-3x^2

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derivative of

3 x^{2} - x^{3}

6 x - 3 x^{2}

Solution steps

\frac{d}{d x} (3 x^{2} - x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (x^{3})

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (x^{3}) = 3 x^{2}

= 6 x - 3 x^{2}

\int \frac{1}{4 x ^{2} + 1} d x

\int \frac{1}{y + y} d y

y^{^{'}} = sin (x^{2})

n = 0 \sum \infty \frac{n + 4}{3 n + 2}

\int (z - 3)^{n} d z

What is the derivative of 3x^2-x^3 ?
The derivative of 3x^2-x^3 is 6x-3x^2
What is the first derivative of 3x^2-x^3 ?
The first derivative of 3x^2-x^3 is 6x-3x^2