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Popular >

f(t)=1+t^2

Solution

f (t) = 1 + t^{2}

Solution

Domain : - \infty < t < \infty

Range : f (t) \geq 1

Y Intercepts : (0, 1)

Vertex : Minimum (0, 1)

Inverse : t - 1, - t - 1

+1

Interval Notation

Domain : (- \infty, \infty)

Range : [1, \infty)

Solution steps

Domain of

1 + t^{2} : - \infty < t < \infty

Range of

1 + t^{2} : f (t) \geq 1

Axis interception points of

1 + t^{2} :

Y Intercepts

: (0, 1)

Vertex of

1 + t^{2} :

Minimum

(0, 1)

Inverse of

1 + t^{2} : t - 1, - t - 1

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x \to 1 + lim (\frac{5}{x ^{2} - 1})

integral of 1/(1+2x)

\int \frac{1}{1 + 2 x} d x

Frequently Asked Questions (FAQ)

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