What is the limit as x approaches 1+of 5/(x^2-1) ?

The limit as x approaches 1+of 5/(x^2-1) is infinity

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limit as x approaches 1+of 5/(x^2-1)

x \to 1 + lim (\frac{5}{x ^{2} - 1})

\infty

Solution steps

x \to 1 + lim (\frac{5}{x ^{2} - 1})

For

x

approaching

1

from the right

, x > 1 \Rightarrow x^{2} - 1 > 0

The denominator is a positive quantity approaching 0 from the right

= \infty

\int \frac{1}{1 + 2 x} d x

x \to 3 lim (4 x)

x \to 3 lim (5 x^{3} - 4 x^{2} + x - 6)

\frac{d}{d x} ((a x^{2} + b x + c) e^{- \frac{x}{2}})

\frac{d ^{4}}{d x ^{4}} (e^{\frac{6}{x}})

What is the limit as x approaches 1+of 5/(x^2-1) ?
The limit as x approaches 1+of 5/(x^2-1) is infinity