What is the derivative of (x^4/(1-x^3)) ?

The derivative of (x^4/(1-x^3)) is (4x^3-x^6)/((1-x^3)^2)

What is the first derivative of (x^4/(1-x^3)) ?

The first derivative of (x^4/(1-x^3)) is (4x^3-x^6)/((1-x^3)^2)

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Popular >

\frac{d}{d x} (\frac{x ^{4}}{1 - x ^{3}})

\frac{4 x ^{3} - x ^{6}}{( 1 - x ^{3} ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{4}}{1 - x ^{3}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{4} ) ( 1 - x ^{3} ) - \frac{d}{d x} ( 1 - x ^{3} ) x ^{4}}{( 1 - x ^{3} ) ^{2}}

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (1 - x^{3}) = - 3 x^{2}

= \frac{4 x ^{3} ( 1 - x ^{3} ) - ( - 3 x ^{2} ) x ^{4}}{( 1 - x ^{3} ) ^{2}}

Simplify

\frac{4 x ^{3} ( 1 - x ^{3} ) - ( - 3 x ^{2} ) x ^{4}}{( 1 - x ^{3} ) ^{2}} : \frac{4 x ^{3} - x ^{6}}{( 1 - x ^{3} ) ^{2}}

= \frac{4 x ^{3} - x ^{6}}{( 1 - x ^{3} ) ^{2}}

\frac{d y}{d x} = \frac{x \cdot y ^{2}}{( x ^{2} + 1 )}

\frac{2}{x x}

x \to \infty lim (x (2))

\frac{d}{d x} (3 A e^{3 x})

4 sin (x), 4 cos (2 x), [- \frac{π}{2}, \frac{π}{6}]

What is the derivative of (x^4/(1-x^3)) ?
The derivative of (x^4/(1-x^3)) is (4x^3-x^6)/((1-x^3)^2)
What is the first derivative of (x^4/(1-x^3)) ?
The first derivative of (x^4/(1-x^3)) is (4x^3-x^6)/((1-x^3)^2)