What is area 4sin(x),4cos(2x),[-pi/2 , pi/6 ] ?

The answer to area 4sin(x),4cos(2x),[-pi/2 , pi/6 ] is 3sqrt(3)

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area 4sin(x),4cos(2x),[-pi/2 , pi/6 ]

area

4 sin (x), 4 cos (2 x), [- \frac{π}{2}, \frac{π}{6}]

33

Decimal Notation

5.19615 \dots

Solution steps

Apply the area formula:

\int_{- \frac{π}{2}}^{\frac{π}{6}} ∣ 4 sin (x) - 4 cos (2 x) ∣ d x

Solve

\int_{- \frac{π}{2}}^{\frac{π}{6}} ∣ 4 sin (x) - 4 cos (2 x) ∣ d x : 33

The area is:

= 33

\frac{\partial}{\partial x} (sin (3 x))

(5 x - 3)^{4} (2 x - 7)^{- 3}

\frac{\partial}{\partial y} (0.2 y - 7)

0.35 (sin (x))

\frac{\partial}{\partial r} (2 rs)

What is area 4sin(x),4cos(2x),[-pi/2 , pi/6 ] ?
The answer to area 4sin(x),4cos(2x),[-pi/2 , pi/6 ] is 3sqrt(3)