What is the solution for y^2+x^2y^'=xyy^' ?

The solution for y^2+x^2y^'=xyy^' is y=-\W(-(c_{1})/x)x

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y^2+x^2y^'=xyy^'

y^{2} + x^{2} y^{^{'}} = x y y^{^{'}}

y = - W (- \frac{c _{1}}{x}) x

Solution steps

y^{2} + x^{2} y^{'} (x) = x y y^{'} (x)

Solve using substitution:

y = - W (- \frac{c _{1}}{x}) x

y = - W (- \frac{c _{1}}{x}) x

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What is the solution for y^2+x^2y^'=xyy^' ?
The solution for y^2+x^2y^'=xyy^' is y=-\W(-(c_{1})/x)x