What is the tangent of sqrt(3x+4),\at x=7 ?

The tangent of sqrt(3x+4),\at x=7 is y= 3/10 x+29/10

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tangent of sqrt(3x+4),\at x=7

tangent of

3 x + 4, at x = 7

y = \frac{3}{10} x + \frac{29}{10}

Solution steps

Find the tangent point:

(7, 5)

Find the slope of

y = 3 x + 4 : \frac{d y}{d x} = \frac{3}{2 3 x + 4}

Compute the slope of

y = 3 x + 4

x = 7 : m = \frac{3}{10}

Find the line with slope m=

\frac{3}{10}

and passing through

(7, 5) : y = \frac{3}{10} x + \frac{29}{10}

y = \frac{3}{10} x + \frac{29}{10}

x \to 0 - lim (x ln (- x))

\frac{d}{d x} (x + sin^{2} (\frac{x}{3}) - 8)

\frac{d}{d x} (- 3^{x})

\int_{0}^{π} sin^{6} (x) d x

2 y^{^{''}} - 2 y^{^{'}} + y = 0

What is the tangent of sqrt(3x+4),\at x=7 ?
The tangent of sqrt(3x+4),\at x=7 is y= 3/10 x+29/10