What is the derivative of-3^x ?

The derivative of-3^x is -3^xln(3)

What is the first derivative of-3^x ?

The first derivative of-3^x is -3^xln(3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (- 3^{x})

- 3^{x} ln (3)

Solution steps

\frac{d}{d x} (- 3^{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d x} (3^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= - 3^{x} ln (3)

\int_{0}^{π} sin^{6} (x) d x

2 y^{^{''}} - 2 y^{^{'}} + y = 0

\int \frac{1}{t} d t

\frac{d}{d x} (- \frac{1}{( x + 4 ) ^{2}})

f (x) = 4 (x^{2} + 4 x)^{3}