What is the sum from n=1 to infinity of 1/(3n-1) ?

The sum from n=1 to infinity of 1/(3n-1) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=1 to infinity of 1/(3n-1)

n = 1 \sum \infty \frac{1}{3 n - 1}

diverges

Solution steps

n = 1 \sum \infty \frac{1}{3 n - 1}

Apply Series Comparison Test:

diverges

= diverges

\int \frac{1}{x ^{2} x ^{2} - 225} d x

\frac{d}{d x} (cot (9 x))

f (x) = - 9 cos (3 x)

\frac{d y}{d x}, ln (x^{2} + y^{2}) = 2 (arctan (\frac{y}{x}))

(0, 15), (6, 0)

What is the sum from n=1 to infinity of 1/(3n-1) ?
The sum from n=1 to infinity of 1/(3n-1) is diverges