What is the derivative of f(x)=-9cos(3x) ?

The derivative of f(x)=-9cos(3x) is 27sin(3x)

What is the first derivative of f(x)=-9cos(3x) ?

The first derivative of f(x)=-9cos(3x) is 27sin(3x)

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derivative of

f (x) = - 9 cos (3 x)

27 sin (3 x)

Solution steps

\frac{d}{d x} (- 9 cos (3 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 9 \frac{d}{d x} (cos (3 x))

Apply the chain rule:

- sin (3 x) \frac{d}{d x} (3 x)

= - sin (3 x) \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x) = 3

= - 9 (- sin (3 x) \cdot 3)

Simplify

= 27 sin (3 x)

\frac{d y}{d x}, ln (x^{2} + y^{2}) = 2 (arctan (\frac{y}{x}))

(0, 15), (6, 0)

x \to 0 lim (7 sec^{2} (7 x))

\frac{\partial}{\partial x} (100 x^{0.66} y^{0.34})

What is the derivative of f(x)=-9cos(3x) ?
The derivative of f(x)=-9cos(3x) is 27sin(3x)
What is the first derivative of f(x)=-9cos(3x) ?
The first derivative of f(x)=-9cos(3x) is 27sin(3x)