What is the derivative of 4t^{(-3)/8} ?

The derivative of 4t^{(-3)/8} is -3/(2t^{11/8)}

What is the first derivative of 4t^{(-3)/8} ?

The first derivative of 4t^{(-3)/8} is -3/(2t^{11/8)}

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derivative of

4 t^{\frac{- 3}{8}}

- \frac{3}{2 t ^{\frac{11}{8}}}

Solution steps

\frac{d}{d t} (4 t^{\frac{- 3}{8}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d t} (t^{\frac{- 3}{8}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 4 \cdot \frac{- 3}{8} t^{\frac{- 3}{8} - 1}

Simplify

4 \cdot \frac{- 3}{8} t^{\frac{- 3}{8} - 1} : - \frac{3}{2 t ^{\frac{11}{8}}}

= - \frac{3}{2 t ^{\frac{11}{8}}}

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What is the derivative of 4t^{(-3)/8} ?
The derivative of 4t^{(-3)/8} is -3/(2t^{11/8)}
What is the first derivative of 4t^{(-3)/8} ?
The first derivative of 4t^{(-3)/8} is -3/(2t^{11/8)}