What is the derivative of (ax/(b+c)) ?

The derivative of (ax/(b+c)) is a/(b+c)

What is the first derivative of (ax/(b+c)) ?

The first derivative of (ax/(b+c)) is a/(b+c)

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\frac{d}{d x} (\frac{a x}{b + c})

\frac{a}{b + c}

Solution steps

\frac{d}{d x} (\frac{a x}{b + c})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{a}{b + c} \frac{d x}{d x}

Apply the common derivative:

\frac{d x}{d x} = 1

= \frac{a}{b + c} \cdot 1

Simplify

= \frac{a}{b + c}

\int \frac{sin ^{4} ( cot ( x ) )}{sin ^{2} ( x )} d x

\frac{\partial}{\partial y} (tan (x^{3} y^{2}))

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What is the derivative of (ax/(b+c)) ?
The derivative of (ax/(b+c)) is a/(b+c)
What is the first derivative of (ax/(b+c)) ?
The first derivative of (ax/(b+c)) is a/(b+c)