What is (\partial)/(\partial u)(u^2v) ?

The answer to (\partial)/(\partial u)(u^2v) is 2uv

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(\partial)/(\partial u)(u^2v)

\frac{\partial}{\partial u} (u^{2} v)

2 uv

Solution steps

\frac{\partial}{\partial u} (u^{2} v)

Treat

v

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= v \frac{\partial}{\partial u} (u^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= v \cdot 2 u^{2 - 1}

Simplify

= 2 uv

\int 12 x^{3} (ln (4 x))^{2} d x

\int (3 x^{2} + 8) d x

y^{^{'}} = \frac{1 - 2 t}{y}

\frac{d}{d x} ((x^{2} + 10)^{6})

x \to 0 lim (\frac{sin ( 6 x ^{2} )}{1 - cos ( 3 x )})

What is (\partial)/(\partial u)(u^2v) ?
The answer to (\partial)/(\partial u)(u^2v) is 2uv