What is the solution for y^'=(1-2t)/y ?

The solution for y^'=(1-2t)/y is y=sqrt(2t-2t^2+c_{1)},y=-sqrt(2t-2t^2+c_{1)}

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y^'=(1-2t)/y

y^{^{'}} = \frac{1 - 2 t}{y}

y = 2 t - 2 t^{2} + c_{1}, y = - 2 t - 2 t^{2} + c_{1}

Solution steps

y^{'} (t) = \frac{1 - 2 t}{y}

Solve separable ODE:

y = 2 t - 2 t^{2} + c_{1}, y = - 2 t - 2 t^{2} + c_{1}

y = 2 t - 2 t^{2} + c_{1}, y = - 2 t - 2 t^{2} + c_{1}

\frac{d}{d x} ((x^{2} + 10)^{6})

x \to 0 lim (\frac{sin ( 6 x ^{2} )}{1 - cos ( 3 x )})

\int (1 + x^{2})^{- 2} d x

(x^{6})^{^{'}}

\frac{d}{d x} (9 + x^{2})

What is the solution for y^'=(1-2t)/y ?
The solution for y^'=(1-2t)/y is y=sqrt(2t-2t^2+c_{1)},y=-sqrt(2t-2t^2+c_{1)}