What is the normal of y=(y+5x)/(3y-x),(1,2) ?

The normal of y=(y+5x)/(3y-x),(1,2) is

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normal of y=(y+5x)/(3y-x),(1,2)

normal of

y = \frac{y + 5 x}{3 y - x}, (1, 2)

Solution steps

y = \frac{y + 5 x}{3 y - x} : y = \frac{x + 1 + x ^{2} + 62 x + 1}{6}, y = \frac{x + 1 - x ^{2} + 62 x + 1}{6}

Slope of the normal line at

(1, 2) : m = \frac{x - x ^{2} + 62 x + 1 - 11}{6 ( x - 1 )}

Find the slope of

y = \frac{x + 1 + x ^{2} + 62 x + 1}{6}, y = \frac{x + 1 - x ^{2} + 62 x + 1}{6} : m_{y} = \frac{1}{6} (- \frac{x + 31}{x ^{2} + 62 x + 1} + 1)

Compute the slope of the normal line:

m = - \frac{6 x ^{2} + 62 x + 1}{- x - 31 + x ^{2} + 62 x + 1}

Solve

\frac{x - x ^{2} + 62 x + 1 - 11}{6 ( x - 1 )} = - \frac{6 x ^{2} + 62 x + 1}{- x - 31 + x ^{2} + 62 x + 1} :

No Solution for

x \in R

\frac{d}{d x} (e^{2 t a n (x)})

1 + t

\int (2 x + 3) e^{2 x} d x

\frac{d}{d t} (e^{2 t} cos (4 t))

f (x) = (x^{4}) x^{2} + 2

What is the normal of y=(y+5x)/(3y-x),(1,2) ?
The normal of y=(y+5x)/(3y-x),(1,2) is