What is the derivative of sqrt(1+t) ?

The derivative of sqrt(1+t) is 1/(2sqrt(1+t))

What is the first derivative of sqrt(1+t) ?

The first derivative of sqrt(1+t) is 1/(2sqrt(1+t))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

1 + t

\frac{1}{2 1 + t}

Solution steps

\frac{d}{d t} (1 + t)

Apply the chain rule:

\frac{1}{2 1 + t} \frac{d}{d t} (1 + t)

= \frac{1}{2 1 + t} \frac{d}{d t} (1 + t)

\frac{d}{d t} (1 + t) = 1

= \frac{1}{2 1 + t} \cdot 1

Simplify

= \frac{1}{2 1 + t}

\int (2 x + 3) e^{2 x} d x

\frac{d}{d t} (e^{2 t} cos (4 t))

f (x) = (x^{4}) x^{2} + 2

\int \frac{48 x}{( x + 1 ) ^{2} ( 3 x + 1 )} d x

t^{2} y^{^{''}} - t (t + 2) y^{^{'}} + (t + 2) y = 0

What is the derivative of sqrt(1+t) ?
The derivative of sqrt(1+t) is 1/(2sqrt(1+t))
What is the first derivative of sqrt(1+t) ?
The first derivative of sqrt(1+t) is 1/(2sqrt(1+t))