What is the tangent of y=-6x^2+4 ?

The tangent of y=-6x^2+4 is y=-12a_{0}x+6a_{0}^2+4

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tangent of y=-6x^2+4

tangent of

y = - 6 x^{2} + 4

y = - 12 a_{0} x + 6 a_{0}^{2} + 4

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, - 6 a_{0}^{2} + 4)

Find the slope of

y = - 6 x^{2} + 4 : \frac{d y}{d x} = - 12 x

Compute the slope of

y = - 6 x^{2} + 4

x = a_{0} : m = - 12 a_{0}

Find the line with slope m=

- 12 a_{0}

and passing through

(a_{0}, - 6 a_{0}^{2} + 4) : y = - 12 a_{0} x + 6 a_{0}^{2} + 4

y = - 12 a_{0} x + 6 a_{0}^{2} + 4

x \to 0 + lim (ln (x) x)

y = \frac{1 - y}{x - 1}

x \to + 7 lim (2 cos (x))

\frac{d}{d x} (2 x^{2} + 4 x + 7)

\frac{\partial}{\partial x} (5 x^{2} + 3 y^{2})

What is the tangent of y=-6x^2+4 ?
The tangent of y=-6x^2+4 is y=-12a_{0}x+6a_{0}^2+4