What is the derivative of y=(1-y)/(x-1) ?

The derivative of y=(1-y)/(x-1) is -1/(x-1)

What is the first derivative of y=(1-y)/(x-1) ?

The first derivative of y=(1-y)/(x-1) is -1/(x-1)

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derivative of

y = \frac{1 - y}{x - 1}

- \frac{1}{x - 1}

Solution steps

\frac{d}{d y} (\frac{1 - y}{x - 1})

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{x - 1} \frac{d}{d y} (1 - y)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{x - 1} (\frac{d}{d y} (1) - \frac{d y}{d y})

\frac{d}{d y} (1) = 0

\frac{d y}{d y} = 1

= \frac{1}{x - 1} (0 - 1)

Simplify

= - \frac{1}{x - 1}

x \to + 7 lim (2 cos (x))

\frac{d}{d x} (2 x^{2} + 4 x + 7)

\frac{\partial}{\partial x} (5 x^{2} + 3 y^{2})

\int \frac{y}{( 1 + y ^{2} ) ^{\frac{1}{2}}} d y

What is the derivative of y=(1-y)/(x-1) ?
The derivative of y=(1-y)/(x-1) is -1/(x-1)
What is the first derivative of y=(1-y)/(x-1) ?
The first derivative of y=(1-y)/(x-1) is -1/(x-1)