What is the derivative of (ax+b^5) ?

The derivative of (ax+b^5) is 5(ax+b)^4a

What is the first derivative of (ax+b^5) ?

The first derivative of (ax+b^5) is 5(ax+b)^4a

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\frac{d}{d x} ((a x + b)^{5})

5 (a x + b)^{4} a

Solution steps

\frac{d}{d x} ((a x + b)^{5})

Apply the chain rule:

5 (a x + b)^{4} \frac{d}{d x} (a x + b)

= 5 (a x + b)^{4} \frac{d}{d x} (a x + b)

\frac{d}{d x} (a x + b) = a

= 5 (a x + b)^{4} a

y = \frac{3}{ln ( x )}

3 \frac{d ^{2} y}{d x ^{2}} + 18 \frac{d y}{d x} + 24 y = 6 sin (2 x)

\int 12 e^{6 x} d x

\frac{1}{3 + 2 x}

\int (x^{4} + x^{2})^{8} (4 x^{3} + 2 x) d x

What is the derivative of (ax+b^5) ?
The derivative of (ax+b^5) is 5(ax+b)^4a
What is the first derivative of (ax+b^5) ?
The first derivative of (ax+b^5) is 5(ax+b)^4a