What is the derivative of ln(3x^2) ?

The derivative of ln(3x^2) is 2/x

What is the first derivative of ln(3x^2) ?

The first derivative of ln(3x^2) is 2/x

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derivative of

ln (3 x^{2})

\frac{2}{x}

Solution steps

\frac{d}{d x} (ln (3 x^{2}))

Apply the chain rule:

\frac{1}{3 x ^{2}} \frac{d}{d x} (3 x^{2})

= \frac{1}{3 x ^{2}} \frac{d}{d x} (3 x^{2})

\frac{d}{d x} (3 x^{2}) = 6 x

= \frac{1}{3 x ^{2}} \cdot 6 x

Simplify

\frac{1}{3 x ^{2}} \cdot 6 x : \frac{2}{x}

= \frac{2}{x}

h (x) = 3 e^{x} - 7 x, (0, 3)

\frac{d}{d x} (e^{t a n (3 x)})

(9, 2), (- 2, 6)

\frac{d}{d x} (\frac{2}{x} - 1)

\frac{( x ^{2} )}{5 + x}

What is the derivative of ln(3x^2) ?
The derivative of ln(3x^2) is 2/x
What is the first derivative of ln(3x^2) ?
The first derivative of ln(3x^2) is 2/x