What is the derivative of 2/x-1 ?

The derivative of 2/x-1 is -2/(x^2)

What is the first derivative of 2/x-1 ?

The first derivative of 2/x-1 is -2/(x^2)

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\frac{d}{d x} (\frac{2}{x} - 1)

- \frac{2}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{2}{x} - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{2}{x}) - \frac{d}{d x} (1)

\frac{d}{d x} (\frac{2}{x}) = - \frac{2}{x ^{2}}

\frac{d}{d x} (1) = 0

= - \frac{2}{x ^{2}} - 0

Simplify

= - \frac{2}{x ^{2}}

\frac{( x ^{2} )}{5 + x}

\frac{d y}{d x} + \frac{y}{x} = 2 x^{2} y^{2}

\frac{d y}{d x} + y = x y^{4}

\int_{0}^{2 π} sin^{2} (θ) d θ

f (x) = 2 x^{2} - 5 x

What is the derivative of 2/x-1 ?
The derivative of 2/x-1 is -2/(x^2)
What is the first derivative of 2/x-1 ?
The first derivative of 2/x-1 is -2/(x^2)