What is the extreme f(x)=3x+2z+4xz ?

The extreme f(x)=3x+2z+4xz is Saddle(-1/2 ,-3/4)

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extreme f(x)=3x+2z+4xz

extreme points

f (x) = 3 x + 2 z + 4 x z

Saddle (- \frac{1}{2}, - \frac{3}{4})

Solution steps

Find the critical points:

(- \frac{1}{2}, - \frac{3}{4})

\frac{\partial ^{2} f}{\partial x ^{2}} = 0

D (x, z) = - 16

Check the sign of at each critical point

Check critical point

(- \frac{1}{2}, - \frac{3}{4}) :

Saddle

Saddle (- \frac{1}{2}, - \frac{3}{4})

\int_{1}^{7} \frac{ln ( x )}{x} d x

x \to 1 lim (3 x^{2})

\frac{\partial}{\partial x} (y^{5 x})

\frac{d}{d x} (4 - e^{x})

\frac{d}{d x} (\frac{( 4 x ^{2} + 2 x + 2 )}{x})

What is the extreme f(x)=3x+2z+4xz ?
The extreme f(x)=3x+2z+4xz is Saddle(-1/2 ,-3/4)