What is the derivative of 4-e^x ?

The derivative of 4-e^x is -e^x

What is the first derivative of 4-e^x ?

The first derivative of 4-e^x is -e^x

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\frac{d}{d x} (4 - e^{x})

- e^{x}

Solution steps

\frac{d}{d x} (4 - e^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4) - \frac{d}{d x} (e^{x})

\frac{d}{d x} (4) = 0

\frac{d}{d x} (e^{x}) = e^{x}

= 0 - e^{x}

Simplify

= - e^{x}

\frac{d}{d x} (\frac{( 4 x ^{2} + 2 x + 2 )}{x})

y^{^{''}} + 6 y^{^{'}} = 162 e^{3 t}, y (0) = 6, y^{^{'}} (0) = 7

t \to \infty lim (\frac{0.2 t}{t ^{2} + 1})

\frac{d}{d x} (2 (- 2 e^{- x^{2}} x^{2} + e^{- x^{2}}))

x \to 5 lim (2 x^{3} - 3 x^{2} - x - 4)