What is the derivative of f(x)=2(2)^4-16(2)^3+8 ?

The derivative of f(x)=2(2)^4-16(2)^3+8 is 0

What is the first derivative of f(x)=2(2)^4-16(2)^3+8 ?

The first derivative of f(x)=2(2)^4-16(2)^3+8 is 0

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derivative of

f (x) = 2 (2)^{4} - 16 (2)^{3} + 8

0

Solution steps

\frac{d}{d x} (2 \cdot 2^{4} - 16 \cdot 2^{3} + 8)

2 \cdot 2^{4} - 16 \cdot 2^{3} + 8 = - 88

= \frac{d}{d x} (- 88)

Derivative of a constant:

\frac{d}{d x} (a) = 0

= 0

y^{^{'}} = - y + sin (x) + cos (x)

f (x) = 3 x + 2 z + 4 x z

\int_{1}^{7} \frac{ln ( x )}{x} d x

x \to 1 lim (3 x^{2})

\frac{\partial}{\partial x} (y^{5 x})

What is the derivative of f(x)=2(2)^4-16(2)^3+8 ?
The derivative of f(x)=2(2)^4-16(2)^3+8 is 0
What is the first derivative of f(x)=2(2)^4-16(2)^3+8 ?
The first derivative of f(x)=2(2)^4-16(2)^3+8 is 0