What is the derivative of 4/(t^2) ?

The derivative of 4/(t^2) is -8/(t^3)

What is the first derivative of 4/(t^2) ?

The first derivative of 4/(t^2) is -8/(t^3)

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derivative of

\frac{4}{t ^{2}}

- \frac{8}{t ^{3}}

Solution steps

\frac{d}{d t} (\frac{4}{t ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d t} (\frac{1}{t ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 4 \frac{d}{d t} (t^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 4 (- 2 t^{- 2 - 1})

Simplify

4 (- 2 t^{- 2 - 1}) : - \frac{8}{t ^{3}}

= - \frac{8}{t ^{3}}

\frac{s}{s ^{2} + s + 3}

\frac{d}{d x} (\frac{4}{3} π r (x) (x)^{3})

\frac{d}{d x} (\frac{- x ^{2} - 8}{( x ^{2} - 8 ) ^{2}})

\frac{d x}{d t} = - \frac{6 x}{20 + 2 t}

\frac{d}{d x} ((3 x^{2} + 1)^{3})

What is the derivative of 4/(t^2) ?
The derivative of 4/(t^2) is -8/(t^3)
What is the first derivative of 4/(t^2) ?
The first derivative of 4/(t^2) is -8/(t^3)