What is the derivative of (3x^2+1^3) ?

The derivative of (3x^2+1^3) is 18x(3x^2+1)^2

What is the first derivative of (3x^2+1^3) ?

The first derivative of (3x^2+1^3) is 18x(3x^2+1)^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} ((3 x^{2} + 1)^{3})

18 x (3 x^{2} + 1)^{2}

Solution steps

\frac{d}{d x} ((3 x^{2} + 1)^{3})

Apply the chain rule:

3 (3 x^{2} + 1)^{2} \frac{d}{d x} (3 x^{2} + 1)

= 3 (3 x^{2} + 1)^{2} \frac{d}{d x} (3 x^{2} + 1)

\frac{d}{d x} (3 x^{2} + 1) = 6 x

= 3 (3 x^{2} + 1)^{2} \cdot 6 x

Simplify

= 18 x (3 x^{2} + 1)^{2}

y = x^{3} - 3 x^{2} - x + 3, - 1 < x \leq 3

x \to 1 + lim (\frac{1}{2} x + 3)

x \to - 1 lim (sin (3 x) + 2)

\frac{d}{d x} (3 x^{4} - 12 x^{3})

x \to 1 lim (\frac{1}{x} - 1)

What is the derivative of (3x^2+1^3) ?
The derivative of (3x^2+1^3) is 18x(3x^2+1)^2
What is the first derivative of (3x^2+1^3) ?
The first derivative of (3x^2+1^3) is 18x(3x^2+1)^2