What is the solution for (dy)/(dx)=\sqrt[3]{x} ?

The solution for (dy)/(dx)=\sqrt[3]{x} is y= 3/4 x^{4/3}+c_{1}

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(dy)/(dx)=\sqrt[3]{x}

y = \frac{3}{4} x^{\frac{4}{3}} + c_{1}

Solution steps

Substitute

\frac{d y}{d x}

with

y^{'} (x)

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \frac{3}{4} x^{\frac{4}{3}} + c_{1}

\int \frac{1}{( x - 1 ) ( x ^{2} + 1 )} d x

y^{^{''}} - 5 y^{^{'}} - 6 y = 12 e^{2} t

\frac{\partial}{\partial x} (y e^{3 x})

\frac{d}{d x} (- 2 (2 x^{2} - 4 x - 1)^{2})

\frac{\partial}{\partial x} (2)

What is the solution for (dy)/(dx)=\sqrt[3]{x} ?
The solution for (dy)/(dx)=\sqrt[3]{x} is y= 3/4 x^{4/3}+c_{1}