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Popular >

derivative of-2(2x^2-4x-1^2)

Solution

\frac{d}{d x} (- 2 (2 x^{2} - 4 x - 1)^{2})

Solution

- 4 (2 x^{2} - 4 x - 1) (4 x - 4)

Solution steps

\frac{d}{d x} (- 2 (2 x^{2} - 4 x - 1)^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 \frac{d}{d x} ((2 x^{2} - 4 x - 1)^{2})

Apply the chain rule:

2 (2 x^{2} - 4 x - 1) \frac{d}{d x} (2 x^{2} - 4 x - 1)

= 2 (2 x^{2} - 4 x - 1) \frac{d}{d x} (2 x^{2} - 4 x - 1)

\frac{d}{d x} (2 x^{2} - 4 x - 1) = 4 x - 4

= - 2 \cdot 2 (2 x^{2} - 4 x - 1) (4 x - 4)

Simplify

= - 4 (2 x^{2} - 4 x - 1) (4 x - 4)

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t \cdot y^{^{'}} + 4 y = 8 t

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y^{^{''}} + 3 y^{^{'}} - 4 y = e^{- 4 x} + x e^{- x}

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\frac{\partial}{\partial x} (z^{x y^{2}})

limit as x approaches 0+of (x-|x|)/(|x|)

x \to 0 + lim (\frac{x - ∣ x ∣}{∣ x ∣})

Frequently Asked Questions (FAQ)

What is the derivative of-2(2x^2-4x-1^2) ?
The derivative of-2(2x^2-4x-1^2) is -4(2x^2-4x-1)(4x-4)
What is the first derivative of-2(2x^2-4x-1^2) ?
The first derivative of-2(2x^2-4x-1^2) is -4(2x^2-4x-1)(4x-4)