What is the derivative of 8pix^2 ?

The derivative of 8pix^2 is 16pix

What is the first derivative of 8pix^2 ?

The first derivative of 8pix^2 is 16pix

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\frac{d}{d x} (8 π x^{2})

16 π x

Solution steps

\frac{d}{d x} (8 π x^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 π \frac{d}{d x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 8 π 2 x^{2 - 1}

Simplify

= 16 π x

f (x) = sin (x) cos (x) - x^{2}

\int x e^{- \frac{2}{5} x} d x

\int \frac{1}{( x - 1 ) ( x ^{2} + 1 )} d x

y^{^{''}} - 5 y^{^{'}} - 6 y = 12 e^{2} t

What is the derivative of 8pix^2 ?
The derivative of 8pix^2 is 16pix
What is the first derivative of 8pix^2 ?
The first derivative of 8pix^2 is 16pix