What is the derivative of 3sqrt(x)-6x ?

The derivative of 3sqrt(x)-6x is 3/(2sqrt(x))-6

What is the first derivative of 3sqrt(x)-6x ?

The first derivative of 3sqrt(x)-6x is 3/(2sqrt(x))-6

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\frac{d}{d x} (3 x - 6 x)

\frac{3}{2 x} - 6

Solution steps

\frac{d}{d x} (3 x - 6 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) - \frac{d}{d x} (6 x)

\frac{d}{d x} (3 x) = \frac{3}{2 x}

\frac{d}{d x} (6 x) = 6

= \frac{3}{2 x} - 6

\int_{1}^{\infty} \frac{1}{x ^{3}} d x

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\int_{0}^{\infty} (a + f (x)) d x

ln (64 sin^{2} (x))

\frac{\partial}{\partial x} (\frac{4}{y ^{2}} + x)

What is the derivative of 3sqrt(x)-6x ?
The derivative of 3sqrt(x)-6x is 3/(2sqrt(x))-6
What is the first derivative of 3sqrt(x)-6x ?
The first derivative of 3sqrt(x)-6x is 3/(2sqrt(x))-6