What is (\partial)/(\partial x)(4/(y^2)+x) ?

The answer to (\partial)/(\partial x)(4/(y^2)+x) is 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(4/(y^2)+x)

\frac{\partial}{\partial x} (\frac{4}{y ^{2}} + x)

1

Solution steps

\frac{\partial}{\partial x} (\frac{4}{y ^{2}} + x)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (\frac{4}{y ^{2}}) + \frac{\partial}{\partial x} (x)

\frac{\partial}{\partial x} (\frac{4}{y ^{2}}) = 0

\frac{\partial}{\partial x} (x) = 1

= 0 + 1

Simplify

= 1

\int e^{x} cos (a x) d x

x \to + 4 lim (\frac{2}{( x + 4 ) ^{3}})

x \to 0 - lim (\frac{x}{x})

\frac{d}{d x} (\frac{x ^{2} - 3 x + 2}{x ^{7} - 2})

\frac{d y}{d x} + \frac{2 x}{1 + x ^{2}} y = \frac{1}{1 + x ^{2}}

What is (\partial)/(\partial x)(4/(y^2)+x) ?
The answer to (\partial)/(\partial x)(4/(y^2)+x) is 1