What is (\partial)/(\partial x)(2z^3*ysin(x)) ?

The answer to (\partial)/(\partial x)(2z^3*ysin(x)) is 2z^3ycos(x)

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(\partial)/(\partial x)(2z^3*ysin(x))

\frac{\partial}{\partial x} (2 z^{3} \cdot y sin (x))

2 z^{3} y cos (x)

Solution steps

\frac{\partial}{\partial x} (2 z^{3} y sin (x))

Treat

z, y

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 z^{3} y \frac{\partial}{\partial x} (sin (x))

Apply the common derivative:

\frac{\partial}{\partial x} (sin (x)) = cos (x)

= 2 z^{3} y cos (x)

t \to - \infty lim (\frac{( - 2 t - 2 )}{e ^{t}})

\int_{0}^{2} sin (π x) d x

\int \frac{π}{x ^{2}} d x

\int \frac{2}{x ^{2} + x + 1} d x

What is (\partial)/(\partial x)(2z^3*ysin(x)) ?
The answer to (\partial)/(\partial x)(2z^3*ysin(x)) is 2z^3ycos(x)