What is the derivative of 2/(\sqrt[4]{16x^3)} ?

The derivative of 2/(\sqrt[4]{16x^3)} is -(3x^2)/(4(x^3)^{5/4)}

What is the first derivative of 2/(\sqrt[4]{16x^3)} ?

The first derivative of 2/(\sqrt[4]{16x^3)} is -(3x^2)/(4(x^3)^{5/4)}

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derivative of

- \frac{3 x ^{2}}{4 ( x ^{3} ) ^{\frac{5}{4}}}

Solution steps

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 2 \frac{d}{d x} ((16 x^{3})^{- \frac{1}{4}})

Apply the chain rule:

- \frac{1}{4 ( 16 x ^{3} ) ^{\frac{5}{4}}} \frac{d}{d x} (16 x^{3})

= - \frac{1}{4 ( 16 x ^{3} ) ^{\frac{5}{4}}} \frac{d}{d x} (16 x^{3})

\frac{d}{d x} (16 x^{3}) = 48 x^{2}

= 2 (- \frac{1}{4 ( 16 x ^{3} ) ^{\frac{5}{4}}} \cdot 48 x^{2})

Simplify

2 (- \frac{1}{4 ( 16 x ^{3} ) ^{\frac{5}{4}}} \cdot 48 x^{2}) : - \frac{3 x ^{2}}{4 ( x ^{3} ) ^{\frac{5}{4}}}

= - \frac{3 x ^{2}}{4 ( x ^{3} ) ^{\frac{5}{4}}}

t \to - \infty lim (\frac{( - 2 t - 2 )}{e ^{t}})

\int_{0}^{2} sin (π x) d x

\int \frac{π}{x ^{2}} d x

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\int 9 - t^{2} d t

What is the derivative of 2/(\sqrt[4]{16x^3)} ?
The derivative of 2/(\sqrt[4]{16x^3)} is -(3x^2)/(4(x^3)^{5/4)}
What is the first derivative of 2/(\sqrt[4]{16x^3)} ?
The first derivative of 2/(\sqrt[4]{16x^3)} is -(3x^2)/(4(x^3)^{5/4)}