What is the limit as x approaches 0 of 1/(1+5^{2/x)} ?

The limit as x approaches 0 of 1/(1+5^{2/x)} is diverges

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limit as x approaches 0 of 1/(1+5^{2/x)}

x \to 0 lim (\frac{1}{1 + 5 ^{\frac{2}{x}}})

diverges

Solution steps

x \to 0 lim (\frac{1}{1 + 5 ^{\frac{2}{x}}})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{1}{1 + 5 ^{\frac{2}{x}}}) = 0

x \to 0 - lim (\frac{1}{1 + 5 ^{\frac{2}{x}}}) = 1

= diverges

\int sin (\frac{1}{3} x) d x

\frac{\partial}{\partial x} (2 sin (3 x))

\frac{d}{d x} (cos^{3} (3 x))

f (x) = 3 x + 7

y = 3^{x - 1}

What is the limit as x approaches 0 of 1/(1+5^{2/x)} ?
The limit as x approaches 0 of 1/(1+5^{2/x)} is diverges