What is (\partial)/(\partial x)(2sin(3x)) ?

The answer to (\partial)/(\partial x)(2sin(3x)) is 6cos(3x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(2sin(3x))

\frac{\partial}{\partial x} (2 sin (3 x))

6 cos (3 x)

Solution steps

\frac{\partial}{\partial x} (2 sin (3 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{\partial}{\partial x} (sin (3 x))

Apply the chain rule:

cos (3 x) \frac{\partial}{\partial x} (3 x)

= cos (3 x) \frac{\partial}{\partial x} (3 x)

\frac{\partial}{\partial x} (3 x) = 3

= 2 cos (3 x) \cdot 3

Simplify

= 6 cos (3 x)

\frac{d}{d x} (cos^{3} (3 x))

f (x) = 3 x + 7

y = 3^{x - 1}

f (x) = \frac{x}{x ^{2} + 9}

y^{^{''}} - 2 y^{^{'}} + 2 y = x + e^{x}

What is (\partial)/(\partial x)(2sin(3x)) ?
The answer to (\partial)/(\partial x)(2sin(3x)) is 6cos(3x)