What is the derivative of sqrt(x)-8x ?

The derivative of sqrt(x)-8x is 1/(2sqrt(x))-8

What is the first derivative of sqrt(x)-8x ?

The first derivative of sqrt(x)-8x is 1/(2sqrt(x))-8

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\frac{d}{d x} (x - 8 x)

\frac{1}{2 x} - 8

Solution steps

\frac{d}{d x} (x - 8 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x) - \frac{d}{d x} (8 x)

\frac{d}{d x} (x) = \frac{1}{2 x}

\frac{d}{d x} (8 x) = 8

= \frac{1}{2 x} - 8

y = 43 x^{2} + (x^{2})^{43}

x \to 2 lim (\frac{2 x ^{2}}{2 x + 2})

\int (2 + tan^{2} (θ)) d θ

\frac{d}{d x} (\frac{5 x}{x ^{2} + 1})

n = 1 \sum \infty \frac{1}{n ^{2} + 3}

What is the derivative of sqrt(x)-8x ?
The derivative of sqrt(x)-8x is 1/(2sqrt(x))-8
What is the first derivative of sqrt(x)-8x ?
The first derivative of sqrt(x)-8x is 1/(2sqrt(x))-8