What is the tangent of y= 1/(sqrt(x)),(1,1) ?

The tangent of y= 1/(sqrt(x)),(1,1) is y=-1/2 x+3/2

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tangent of y= 1/(sqrt(x)),(1,1)

tangent of

y = \frac{1}{x}, (1, 1)

y = - \frac{1}{2} x + \frac{3}{2}

Solution steps

Find the slope of

y = \frac{1}{x} : \frac{d y}{d x} = - \frac{1}{2 x ^{\frac{3}{2}}}

Compute the slope of

y = \frac{1}{x}

(1, 1) : m = - \frac{1}{2}

Find the line with slope m=

- \frac{1}{2}

and passing through

(1, 1) : y = - \frac{1}{2} x + \frac{3}{2}

y = - \frac{1}{2} x + \frac{3}{2}

\frac{d}{d x} ((x^{2} + 3 x - 9) e^{x})

\frac{d}{d x} (x^{3} + k y (x)^{2} - 5 x y)

\frac{16 x}{x ^{2} + 16}, at - 2, - \frac{8}{5}

\frac{\partial}{\partial x} (2 e^{x y})

\int \frac{2 - x ^{2}}{x} d x

What is the tangent of y= 1/(sqrt(x)),(1,1) ?
The tangent of y= 1/(sqrt(x)),(1,1) is y=-1/2 x+3/2