What is the tangent of f(x)=4sqrt(x) ?

The tangent of f(x)=4sqrt(x) is y= 2/(sqrt(a_{0))}x+2sqrt(a_{0)}

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tangent of f(x)=4sqrt(x)

tangent of

f (x) = 4 x

y = \frac{2}{a _{0}} x + 2 a_{0}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 4 a_{0})

Find the slope of

f (x) = 4 x : \frac{df ( x )}{d x} = \frac{2}{x}

Compute the slope of

f (x) = 4 x

x = a_{0} : m = \frac{2}{a _{0}}

Find the line with slope m=

\frac{2}{a _{0}}

and passing through

(a_{0}, 4 a_{0}) : y = \frac{2}{a _{0}} x + 2 a_{0}

y = \frac{2}{a _{0}} x + 2 a_{0}

sin (4 t)

f (x) = cos (2 x) + sin (2 x)

\frac{2.25 r}{( r + 0.5 ) ^{2}}

\int (x^{2} + x + 1) d x

\int cos (θ) sin^{2} (θ) d θ

What is the tangent of f(x)=4sqrt(x) ?
The tangent of f(x)=4sqrt(x) is y= 2/(sqrt(a_{0))}x+2sqrt(a_{0)}