What is laplacetransform sin(4t) ?

The answer to laplacetransform sin(4t) is 4/(s^2+16)

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laplacetransform sin(4t)

laplace transform

sin (4 t)

\frac{4}{s ^{2} + 16}

Solution steps

L {sin (4 t)}

Use Laplace Transform table:

L {sin (a t)} = \frac{a}{s ^{2} + a ^{2}}

L {sin (4 t)} = \frac{4}{s ^{2} + 4 ^{2}}

= \frac{4}{s ^{2} + 4 ^{2}}

= \frac{4}{s ^{2} + 16}

f (x) = cos (2 x) + sin (2 x)

\frac{2.25 r}{( r + 0.5 ) ^{2}}

\int (x^{2} + x + 1) d x

\int cos (θ) sin^{2} (θ) d θ

\frac{\partial}{\partial y} (x^{2} cos (e^{x y}))

What is laplacetransform sin(4t) ?
The answer to laplacetransform sin(4t) is 4/(s^2+16)