What is the solution for (dy)/(dt)+2/t y=4t-3+2/t ?

The solution for (dy)/(dt)+2/t y=4t-3+2/t is y=t^2-t+1+(c_{1})/(t^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dt)+2/t y=4t-3+2/t

\frac{d y}{d t} + \frac{2}{t} y = 4 t - 3 + \frac{2}{t}

y = t^{2} - t + 1 + \frac{c _{1}}{t ^{2}}

Solution steps

\frac{d y}{d t} + \frac{2}{t} y = 4 t - 3 + \frac{2}{t}

Solve linear ODE:

y = t^{2} - t + 1 + \frac{c _{1}}{t ^{2}}

y = t^{2} - t + 1 + \frac{c _{1}}{t ^{2}}

x \to 10 lim (\frac{x - 1 - 3}{x - 10})

7 u + 2 u

n = 0 \sum \infty (sin (100))^{n}

\int \frac{x}{x} d x

\int [\frac{2 ^{(18 x)}}{4}] d x

What is the solution for (dy)/(dt)+2/t y=4t-3+2/t ?
The solution for (dy)/(dt)+2/t y=4t-3+2/t is y=t^2-t+1+(c_{1})/(t^2)