What is the integral of [(2^{(18x)})/4 ] ?

The integral of [(2^{(18x)})/4 ] is (2^{18x-3})/(9ln(2))+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of [(2^{(18x)})/4 ]

\int [\frac{2 ^{(18 x)}}{4}] d x

\frac{2 ^{18 x - 3}}{9 ln ( 2 )} + C

Solution steps

\int \frac{2 ^{18 x}}{4} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int 2^{18 x} d x

Apply Integration By Parts

: 26214 4^{x} x - \int 9 ln (2) \cdot 2^{18 x + 1} x d x

= \frac{1}{4} (26214 4^{x} x - \int 9 ln (2) \cdot 2^{18 x + 1} x d x)

\int 9 ln (2) \cdot 2^{18 x + 1} x d x = 26214 4^{x} x - \frac{2 ^{18 x - 1}}{9 ln ( 2 )}

= \frac{1}{4} (26214 4^{x} x - (26214 4^{x} x - \frac{2 ^{18 x - 1}}{9 ln ( 2 )}))

Simplify

\frac{1}{4} (26214 4^{x} x - (26214 4^{x} x - \frac{2 ^{18 x - 1}}{9 ln ( 2 )})) : \frac{2 ^{18 x - 3}}{9 ln ( 2 )}

= \frac{2 ^{18 x - 3}}{9 ln ( 2 )}

Add a constant to the solution

= \frac{2 ^{18 x - 3}}{9 ln ( 2 )} + C

\int 40 x^{3} - 2 d x

y = \frac{8 x}{x ^{2} + 1}, (1, 4)

\int \frac{5 - 4 x ^{3} + 2 x ^{6}}{x ^{6}} d x

\int sin (2 x + 4) d x

\frac{d}{d x} (\frac{sin ( x )}{1 - 2 cos ( x )})

What is the integral of [(2^{(18x)})/4 ] ?
The integral of [(2^{(18x)})/4 ] is (2^{18x-3})/(9ln(2))+C